Transcripción 11/6/2025, 11:28:56 a.m.
What is the correct value of y in the equation (√247)² + y² = 192²?
Notes
• Mathematical Equations and Calculations: (√247)² + y² = 192² 247 + y² = 36,864 y² = 36,864 - 247 y² = 36,617 y = √36,617 ≈ 191.36 (Note: The original transcription states y = 1114, which appears incorrect based on the calculation. The correct value should be approximately 191.36.) X = √38 EF = √114 FG = √247 (√38)² = 38 X = √78 X = 6 X = 7.8 13 = X X = 7.8 (√13)² = c² 7.8 + 1 = c² 8.8 = c² (247)² = c² c = √247 ≈ 15.75 • Geometry and Distance Calculations: X = √78 EF = (value missing) FG = (value missing) C, F, E, G, H, 13, 78, 4, 6, X X² = 78 X = √78 Using the Pythagorean theorem: (√78)² + 13² = c² 78 + 169 = c² 247 = c² c = √247 ≈ 15.75 • Personal and Academic Information: Name: Juan Carlos Huerta Period: 4 Standard 14, 15, 16 Assessment • Standard 14: 1) Convert the following expressions into a + bi form: a. (12 + 8i) + (18 + 15i) = 30 + 23i b. (19 - 15i) = (23 - 12i) = -4 - 3i c. (56i + 7) - (18 - 24i) = (7 + 56i) - (18 - 24i) = (7 - 18) + (56i + 24i) = -11 + 80i d. (1 + 13i)(12 + 18i) *hint: FOIL* = 1*12 + 1*18i + 13i*12 + 13i*18i = 12 + 18i + 156i + 234i² = 12 + (18i + 156i) + 234(-1) = 12 + ...
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