Formación de compuestos iónicos y nomenclatura inorgánica

Apuntes

• Subtopic: Ionic Compounds Formation In forming ionic compounds, the total charge must equal zero. For example: - $Ca^{2+} + SO_4^{2-} \rightarrow CaSO_4$ (Calcium Sulfate) - Charges: +2 and -2, which sum to 0. - $NH_4^+ + ClO_4^- \rightarrow NH_4ClO_4$ (Ammonium Perchlorate) - Charges: +1 and -1, which sum to 0. - $Ca^{2+} + Cl_2^- \rightarrow CaCl_2$ (Calcium Chloride) - Charges: +2 and -2, which sum to 0. - $Na^+ + O^{2-} \rightarrow Na_2O$ (Sodium Oxide) - Charges cancel out. - $Al^{3+} + (SO_4)^{2-} \rightarrow Al_2(SO_4)_3$ (Aluminum Sulfate) - Charges: +6 and -6, which sum to 0. - $NH_4^+ + NO_3^- \rightarrow NH_4NO_3$ (Ammonium Nitrate) - Charges cancel out. - $Na^+ + I^- \rightarrow NaI$ (Sodium Iodide) - Charges cancel out. - $K^+ + SCN^- \rightarrow KSCN$ (Potassium Thiocyanate) - Charges: +1 and -1, which sum to 0. - $Ag^+ + OH^- \rightarrow AgOH$ (Silver Hydroxide) - Charges: +1 and -1, which sum to 0. - $Co^{2+} + ClO_3^- \rightarrow Co(ClO_3)_2$ (Cobalt(II) Chlorate) - Charges: +2 and -2, which sum to 0. - $Ba^{2+} + CrO_4^{2-} \rightarrow BaCrO_4$ (Barium Chromate) - Charges: +2 and -2, which sum to 0. - $Fe^{3+} + NO_3^- \rightarrow Fe(NO_3)_3$ (Iron(III) Nitrate)...