Tramo 3 - 3

Apuntes

**Tramo 3 - 3** 0 ≤ x ≤ 2 \[ h = \frac{1000}{2} = 500 \] \[ h = 500 (2 - x) \] **Carga 1:** \[ \text{Carga 1} = (1000 - 500x) \times x \] **Carga 2:** \[ \text{Carga 2} = \left[ 1000 + (1000 - 500x) \times x \right] \times \frac{x}{2} = (600 x) \times \frac{x}{2} = 250 x^2 \] **Sumatorio de momentos en el soporte (ΣM₀):** \[ \Sigma M_0 = 0 \] **Ecuación de equilibrio:** \[ \mu_3 + \frac{(1000 - 500x) \times x}{2} + \frac{250 x^2}{(2/3)} = 0 \] Simplificando: \[ \mu_3 + (1000 - 500x) \frac{x}{2} + 166.67 x^3 = 0 \] Por lo tanto, \[ \mu_3 = 500 x^2 - 83.33 x^3 \] --- **Subtema: Tramo 1-1** \[ I_4 = \text{Max} - 5 \times Rax + 166.67 \] Integral: \[ \text{Ec. O}_2 = Rax^+ - 5 Rax + 166.67 x + C_1 \] Ecuación ϕ: \[ \phi = \frac{Rax^2}{6} - \frac{5 Rax^2}{2} + 166.67 x^2 + C_1 + C_2 \] --- **Subtema: Tramo 2-2** \[ \mu_2 = Rax^+ - 5 Rax - 600 x + 166.67 \] Integral: \[ \text{Ec. O}_3 = \frac{Rax^2}{4} - \frac{5 Rax^2}{2} - 300 x^2 + 166.67 x + C_3 \] Diferencial: \[ d_1 \equiv \text{Ec. } \Upsilon T_1 \equiv \frac{Rax^3}{6} - \frac{5 Rax^3}{2} - 100 x^3 + 166.67 x^2 + C_4 \] --- **Notas:** - Se asume que Rax representa una variable o funció...