OPERACIONES -1 VECTOR VALOR

Apuntes

• OPERACIONES - VECTOR VALOR A = (200 km, 0) Eje-X A = (200 km, 180°) Eje-X A = (-200 km + 0 j) km. B = (110 m/s, 40°) B = (110 m/s, 120°) R = (-86.42 i + 114.91 j) m/s. -1/2 S = -A × C = 3/2 Z Esc.: 1 - √0. Hallar: -2A + 3/2 B - C - Z D A = (110 m, 200°) → A = (-140.9 m, -1.20 j) m B = (200 m, 40°) → B = (-128.76 m, -13.2 j) m C = (110 m, 300°) → C = (+7 j - 129.9 m) D = (200 m, N 80°) → D = -141.42 i + 141.42 j m Nuevo vector: -2A = (+281.90 i + 102.6 j) m 3/2 Z = (-192.84 - 229.81 j) m - C = (-7 j + 199.9 j) m - Z delta = (+70.71 i - 70.71 j) m Z = (84.27 i - 68.02 j) m Z = (1 - 0 i² - 1.36 j²) m --- • OPERACIONES - VECTOR BASE A = (200 km, 0) Eje - x A = (260 km, 180°) Eje - x A = (-200 km + 0 j) km. P = (110 m/s, √40°) β = (110 m/s, 120°) R = (-96.42 i + 114.91 j) m/s. -1/2 f = -A² / C² + 3/2 g² Esc.: 1 - √0. Hallar: -2A + 3/2 R - C - 1/2 D A = (110 m, 200°) → A = (-140.9 km, -1.20 j) m β = (200 m, ⁴⁰°) → β = (-128.96 m, -13.2 j) m C = (110 m, 300°) → C = +7.5 j - 1299.1 m D = (200 m, √00) → D = -141.42 i + 141.42 j m Nuevo vector: -2A = (+281.90 i + 102.6 j) m 3/2 Z = (-192.84 - 292.81 j) m C...