11 lim2 3 3
Apuntes
• Limit Calculations: 1) \(\lim_{x \to 2} 3 = 3\) 2) \(\lim_{x \to 2} x^2 = (2)^2 = 4\) 3) \(\lim_{x \to 2} (4x^2 + 3) = \lim_{x \to 2} 4x^2 + \lim_{x \to 2} 3 = 4(2)^2 + 3 = 16 + 3 = 19\) 4) \(\lim_{x \to 1} (x^2 + x + 4) = (1)^2 + 1 + 4 = 1 + 1 + 4 = 6\) Note: In the third limit, the correct evaluation is 16 + 3 = 19, not "lim 16 + 3." Also, in the fourth limit, the expression evaluates to 6, not 3.
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