Análisis de redes de resistencias y equivalencias en circuitos (serie y paralelo)

Anotacoes

# Curto Circuito   $$ R e q _ {1} = \frac {R}{n} = \frac {2 0}{2} = 1 0 \Omega \quad R e q _ {2} = R e q _ {3} = \frac {R}{n} = \frac {1 2}{2} = 6 \Omega \quad R e q _ {4} = \frac {R _ {1} \cdot R _ {2}}{R _ {1} + R _ {2}} = \frac {1 2 \cdot 4}{1 2 + 4} = 3 \Omega $$   $$ R e q _ {5} = \frac {R}{n} = \frac {1 2}{3} = 4 \Omega \quad R e q _ {l} = \sum R = 1 0 + 4 + 3 = 1 7 \Omega $$   $$ R e q _ {1} = \frac {R}{n} = \frac {4 0}{2} = 2 0 \Omega $$ $$ R e q _ {2} = \sum R = 1 0 + 2 0 = 1 0 0 \Omega $$ $$ R e q _ {5} = \frac {R}{n} = \frac {1 0 0}{2} = 5 0 \Omega $$  $$ R e q _ {4} = \sum R = 5 0 + 5 0 = 1 0 0 \Omega $$ $$ R e q _ {l} = \frac {R}{n} = \frac {1 0 0}{2} = 5 0 \Omega $$     $$ \begin{array}{l} \text {t e s}) \\ \hline \begin{array}{c c} & R \\ & 2 R \end{array} \quad \begin{array}{c c} & L \\ & R \end{array} \\ \text {ch c h r t c} \quad 1 = \frac {1}{\varepsilon R} = \frac {U}{2 R} \qu...