Transcrição 31/08/2025, 10:32:18
What is the original trigonometric expression involving cos(3π/2), sin(3π/2 - x), and tan(3π/2 - x)?
Anotacoes
• Subtopic: Simplification of Trigonometric Expressions Simplify: cos(3π/2) · sin(3π/2 - x) · tan(3π/2 - x) sin(5π/2) · cos(5π) · sin(x) · cos(3π/2 - x) (1) cos(3π) · cos(x) · sin(x) · (sin(6π) · cos(6π) · sin(x)) cos(6π) · cos(3π) · sin(6π) · sin(x) 4 · cos(10°) · cos(50°) · cos(70°) 4 · ½ · [cos(-40°) + cos(60°)] · cos(70°) (2) (2 · cos(40°) + 2 · ½) · cos(70°) 2 · cos(40°) · cos(70°) + cos(70°) 2 · ½ · [cos(-30°) + cos(110°)] + cos(70°) = cos(30°) + cos(10°) + cos(70°) = √3/2 + 2 · cos(110° + 70°) · cos(110° - 70°) = √3/2 + 2 · cos(180°) · cos(40°) = √3/2 + 2 · (-1) · cos(40°) = √3/2 - 2 · cos(40°) (Note: The last expression simplifies to the final value, but based on the original steps, the key points are the transformations and the use of cosine sum and difference formulas.)
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